Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A ball of mass m falls vertically to the ground from a height h 1 and rebound to a height $h_2$ . The change in momentum of the ball on striking the ground is
Text Solution
Verified by ExpertsThe correct answer is:
B
When ball falls vertically downward from height $h_1$ its velocity $\vec{v}_1 = \sqrt{2gh_1}$
and its velocity after collision $\vec{v}_2 = \sqrt{2gh_2}$
Change in momentum
$\Delta \vec{P} = m(\vec{v}_2 - \vec{v}_1) = m(\sqrt{2gh_1} + \sqrt{2gh_2})$
(because \vec{v}_1 and \vec{v}_2 are opposite in direction)
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